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905 MATH 2010

Wednesday, May 4, 2011. Jomaris Post for May 4, 2011. Today we learned about perpendicular bisectors. These are lines that bisect straight lines at 90. Heres how to make one. We made these bisectors for several chords. In a circle, we dont need to make crossed arcs on one side of the chord because of the center. After wards, we answered a problem involving bisectors. It was similar to this. This is what we have to work with. WE COULD USE THE PYTHAGORAS THEOREM TO FIND B. 178; bc. 8730; b .

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905 MATH 2010

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Wednesday, May 4, 2011. Jomaris Post for May 4, 2011. Today we learned about perpendicular bisectors. These are lines that bisect straight lines at 90. Heres how to make one. We made these bisectors for several chords. In a circle, we dont need to make crossed arcs on one side of the chord because of the center. After wards, we answered a problem involving bisectors. It was similar to this. This is what we have to work with. WE COULD USE THE PYTHAGORAS THEOREM TO FIND B. 178; bc. 8730; b .

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This web page spmath90510.blogspot.com states the following, "Wednesday, May 4, 2011." We saw that the webpage said " Jomaris Post for May 4, 2011." It also said " Today we learned about perpendicular bisectors. These are lines that bisect straight lines at 90. Heres how to make one. We made these bisectors for several chords. In a circle, we dont need to make crossed arcs on one side of the chord because of the center. After wards, we answered a problem involving bisectors. It was similar to this. This is what we have to work with. WE COULD USE THE PYTHAGORAS THEOREM TO FIND B."

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