Thinking Out Loud

Saturday, November 04, 2006. Two fundamental things to prove. An ensemble average over all QM states is the same as an ensemble average over all states of a complete eigenbasis. The trace of an operator is basis-independent. Any basis? Or just orthogonal bases? Tuesday, October 31, 2006. Why are there no providers that give unlimited cellphone usage for a flat fee. There is even such a thing for data on a cell phone. Could it be bc the business is in people going over their minutes? If the buildings we.

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Thinking Out Loud

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Saturday, November 04, 2006. Two fundamental things to prove. An ensemble average over all QM states is the same as an ensemble average over all states of a complete eigenbasis. The trace of an operator is basis-independent. Any basis? Or just orthogonal bases? Tuesday, October 31, 2006. Why are there no providers that give unlimited cellphone usage for a flat fee. There is even such a thing for data on a cell phone. Could it be bc the business is in people going over their minutes? If the buildings we.

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This web page rztol.blogspot.com states the following, "Saturday, November 04, 2006." We saw that the webpage said " Two fundamental things to prove." It also said " An ensemble average over all QM states is the same as an ensemble average over all states of a complete eigenbasis. The trace of an operator is basis-independent. Any basis? Or just orthogonal bases? Tuesday, October 31, 2006. Why are there no providers that give unlimited cellphone usage for a flat fee. There is even such a thing for data on a cell phone. Could it be bc the business is in people going over their minutes? If the buildings we."

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